H-Index

Given an array of citations (each citation is a non-negative integer) of a researcher, write a function to compute the researcher’s h-index.

According to the definition of h-index on Wikipedia: “A scientist has index h if h of his/her N papers have at least h citations each, and the other N − h papers have no more than h citations each.”

For example, given citations = [3, 0, 6, 1, 5], which means the researcher has 5 papers in total and each of them had received 3, 0, 6, 1, 5 citations respectively. Since the researcher has 3 papers with at least 3 citations each and the remaining two with no more than 3 citations each, his h-index is 3.

Note: If there are several possible values for h, the maximum one is taken as the h-index.

Solution

需要明白h-index指数是怎么计算的,可以参考上面给的链接:
Wikipediap–h-index

Python

1
2
3
4
5
6
7
8
9
10
11
class Solution(object):
def hIndex(self, citations):
"""
:type citations: List[int]
:rtype: int
"""
citations = sorted(citations,reverse=True)
for index,value in enumerate(citations):
if index+1 > value:
return index
return len(citations)

Java

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22

// 来自讨论区

public int hIndex(int[] citations) {
int n = citations.length;
int[] buckets = new int[n+1];
for(int c : citations) {
if(c >= n) {
buckets[n]++;
} else {
buckets[c]++;
}
}
int count = 0;
for(int i = n; i >= 0; i--) {
count += buckets[i];
if(count >= i) {
return i;
}
}
return 0;
}